MATH SOLVE

2 months ago

Q:
# A man jogs at a speed of 0.96 m/s. His dog waits 2.3 s and then takes off running at a speed of 3.4 m/s to catch the man. How far will they have each traveled when the dog catches up with the man

Accepted Solution

A:

When the dog starts running, the man has jogged (0.96 * 2.3 = 2.208) meters.

We can set up an equation to solve for T

2.208 + 0.96T = 3.4T

2.208 = 2.44T

T = 0.904918

You can use either side of the previous equation to evaluate the distance traveled.

2.208 + 0.96 * 0.904918 = 3.076721 meters

3.4 * 0.904918 = 3.076721 meters

We can set up an equation to solve for T

2.208 + 0.96T = 3.4T

2.208 = 2.44T

T = 0.904918

You can use either side of the previous equation to evaluate the distance traveled.

2.208 + 0.96 * 0.904918 = 3.076721 meters

3.4 * 0.904918 = 3.076721 meters